25y^2-10y+4=0

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Solution for 25y^2-10y+4=0 equation:


Simplifying
25y2 + -10y + 4 = 0

Reorder the terms:
4 + -10y + 25y2 = 0

Solving
4 + -10y + 25y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
25 the coefficient of the squared term: 

Divide each side by '25'.
0.16 + -0.4y + y2 = 0

Move the constant term to the right:

Add '-0.16' to each side of the equation.
0.16 + -0.4y + -0.16 + y2 = 0 + -0.16

Reorder the terms:
0.16 + -0.16 + -0.4y + y2 = 0 + -0.16

Combine like terms: 0.16 + -0.16 = 0.00
0.00 + -0.4y + y2 = 0 + -0.16
-0.4y + y2 = 0 + -0.16

Combine like terms: 0 + -0.16 = -0.16
-0.4y + y2 = -0.16

The y term is -0.4y.  Take half its coefficient (-0.2).
Square it (0.04) and add it to both sides.

Add '0.04' to each side of the equation.
-0.4y + 0.04 + y2 = -0.16 + 0.04

Reorder the terms:
0.04 + -0.4y + y2 = -0.16 + 0.04

Combine like terms: -0.16 + 0.04 = -0.12
0.04 + -0.4y + y2 = -0.12

Factor a perfect square on the left side:
(y + -0.2)(y + -0.2) = -0.12

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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